Hey there,

I know this is somewhat a basic question, but got to have it right.

Given a joint distribution p(x,y) and a set of parameters w,

We have a posterior of w given by

p(w|x,y)=p(w)*p(y|x,w)/p(y|x)

P(y|x) is defined as the marginal likelihood, that is, we marginilized w out, by doing the integral of p(x,y,w) over w.

My question is, what is the actual meaning of this likelihood, I have been looking at it from a gaussian process perspective, but the wikipedia page has as an explanation that it helps us decide which models fits the data the best.

Other than this, does it have a more profound meaning.

Thanks

asked Jan 05 '11 at 02:11

Leon%20Palafox's gravatar image

Leon Palafox
31265471107


2 Answers:

int dw P(y|x,w)P(w) = P(y|x) is, as Philemon wrote, the posterior distribution of y given x, according to your model. If your model is a gaussian process, this will be a normal distribution that tells you the expected value of y according to your model and the confidence the model has in this model.

answered Jan 05 '11 at 04:23

Alexandre%20Passos's gravatar image

Alexandre Passos ♦
1896744214334

edited Jan 05 '11 at 04:24

SO it basically helps us to select which Covariance Matrix works best for the same data?

(Jan 05 '11 at 05:28) Leon Palafox

Yes. If you look at P(y|x) for the training/validation set you can choose a covariance function K (not matrix, as the space is infinite-dimensional) that maximizes P(y|x,K)P(K)

(Jan 05 '11 at 07:09) Alexandre Passos ♦

I'm not 100% sure what kind of answer you are looking for. As the wikipedia page mentions, when you integrate w out p(y|x) is only conditioned on the type of model you used and no specific parametrization of it. You generally also use this quantity to make predictions in a Bayesian setting about y for new values of x. A more correct notation would be p(y|x,M) in which M identifies your model architecture.

answered Jan 05 '11 at 04:16

Philemon%20Brakel's gravatar image

Philemon Brakel
153092244

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